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# hmmm...
dnb(x)=nbo{[exp(Vbe/Vt)-1]sinh((xb-x)/Lb)-sinh(x/Lb)}/sinh(xb/Lb)

oops wrong screen! :p
(, Tue 8 Apr 2003, 3:06, archived)
#

dnb(x)=nbo
{[exp(Vbe/Vt)
-1]sinh
((xb-x)
/Lb)
-sinh
(x/Lb)
}/sinh(xb/Lb)
(, Tue 8 Apr 2003, 3:09, archived)
# heheheh :)
(, Tue 8 Apr 2003, 3:11, archived)
# say what you will,
but sometimes I even suprise myself at what i can do.
(, Tue 8 Apr 2003, 3:11, archived)
# you stopped suprising me
a while ago

Nothing is impossible for Fnord...

;)
(, Tue 8 Apr 2003, 3:14, archived)