But but but
is that thing I did with the "t" to find the "x" legal? I was totally ad-libing there...
( ,
Thu 12 Dec 2013, 17:17,
archived)
seems ok as you did define x, t, dx, dt, might be worth showing dx/dt or dt/dx to show how you got dx & dt though...
As far as I can see your equals signs hold everywhere which means it must be true! If the question didn't demand a specific substitution you should be fine. Merry Christams and good luck, also what is your field of study?
( ,
Thu 12 Dec 2013, 18:02,
archived)
Engineering watch officer
Aka officer that's a mechanic on-board big ships (500 tons up).
Started last year. Passed all my exams except maths...
So I'm on the lookout for math trickery involving integrals and derivatives.
( ,
Thu 12 Dec 2013, 18:06,
archived)
Started last year. Passed all my exams except maths...
So I'm on the lookout for math trickery involving integrals and derivatives.
And trigonemetry
But the calculus kind...
Cos(x)^3=cos(1-sin(x)^2) mumbo jumbo.
I'm so shit at trigo...
That's why I do thermodynamics and no map reading.
( ,
Thu 12 Dec 2013, 18:17,
archived)
Cos(x)^3=cos(1-sin(x)^2) mumbo jumbo.
I'm so shit at trigo...
That's why I do thermodynamics and no map reading.
Trig is a bastard, it's worth knowing the complex exponential forms of sine and cosine as you can then avoid trying to remember the identities.
ie.
sin(x)=1/(2i)(e^(ix)-e^(-ix))
and,
cos(x)=1/2(e^(ix)+e^(-ix)
where,
i=sqrt(-1) (you might know 'i' as 'j')
Other than that I can only tell you the trick to learning maths is do lots of problems,
until your sick of em...
and then do some more.
Good luck with your studies :D
( ,
Thu 12 Dec 2013, 20:34,
archived)
sin(x)=1/(2i)(e^(ix)-e^(-ix))
and,
cos(x)=1/2(e^(ix)+e^(-ix)
where,
i=sqrt(-1) (you might know 'i' as 'j')
Other than that I can only tell you the trick to learning maths is do lots of problems,
until your sick of em...
and then do some more.
Good luck with your studies :D