nice one and becuase this doesnt deserve its own thread:
From the Anti-Valentines challenge. See all 275 entries (closed)
( , Wed 7 Feb 2007, 22:26, archived)
(x^2 + y^2 +1)^3 - x^2 * y^3 = 0
not quite anti valentine, but its kinda mathmo, and mathmo's are pretty anti valentine
not quite anti valentine, but its kinda mathmo, and mathmo's are pretty anti valentine
From the Anti-Valentines challenge. See all 275 entries (closed)
( , Wed 7 Feb 2007, 22:26, archived)