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# Simple . . .
A = B
A2 = AB
A2 - B2 = AB - B2
Factoring yields (A + B)(A - B) = B(A - B)
Dividing both sides by (A - B) yields (A + B) = B
Since A = B, substituting B for A yields B + B = B
Therefore 2B = B
Dividing both sides by B yields 2 = 1
(, Sat 25 Jul 2009, 1:09, archived)
# ERROR: DIVIDE BY ZERO
(, Sat 25 Jul 2009, 1:11, archived)
# SAVED BY . . .
F:":":zzy M;';';';'th . . .
(, Sat 25 Jul 2009, 1:13, archived)
# 418: I'm a teapot
(, Sat 25 Jul 2009, 1:15, archived)
# Handleable . . .

^
(, Sat 25 Jul 2009, 1:22, archived)
# or
[(A+B)(A-B)]/[(A-B)(A+B)]=(AB/BAB)(BABABAAB), then the show tune strikes up and we all come out with peacock feathers in out hats.
(, Sat 25 Jul 2009, 1:45, archived)
# Pluckin' good idea !
(, Sat 25 Jul 2009, 1:54, archived)
# hahaha
(, Sat 25 Jul 2009, 2:16, archived)