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This is a normal post It's in the definition.
Normal distribution with mean at 100 and standard deviation of 15.

The range is theoretically infinite, with the actual min and max IQ values determined by the current global population. But of course you knew that, being mathematically literate and all.
 (DestructoLettuce, Wed 10 Dec 2014, 0:41, Reply)
This is a normal post Math is a language I don't speak, so I'll just have to trust you.

(I helped save b3ta! gunmetal drove slowly in the passing lane on, Wed 10 Dec 2014, 0:52, Reply)
This is a normal post Never trust numbers!

(DestructoLettuce, Wed 10 Dec 2014, 0:55, Reply)
This is a normal post Not even numberwang?

(I helped save b3ta! stuj (^(^;;^)^) GO TEAM SPIDERS!(^(^;;^)^), Wed 10 Dec 2014, 1:12, Reply)
This is a normal post You dropped this 's'

(I helped save b3ta! Cerebus Sticky! Sticky! Stick! Stick!, Wed 10 Dec 2014, 8:41, Reply)
This is a normal post haha, the idea is funny, but IQ is an index of performance on a test, not intelligence
and since points can only be assigned in the tests, not subtracted, its range has upper and lower bounds at least a lower limit.

You can describe data as being normally distributed even if it's impossible for points to fall above or below a certain limit, like finish times in a race or something.
 (I helped save b3ta! the prick of misery pierced my foot on a spiiiike on, Wed 10 Dec 2014, 1:21, Reply)
This is a normal post ^this^

(I helped save b3ta! The Awful Puppy Bakery is still bored, Wed 10 Dec 2014, 1:25, Reply)
This is a normal post I answered that. You just need more people.

(DestructoLettuce, Wed 10 Dec 2014, 9:01, Reply)
This is a normal post no matter how many people you test, you will not find a negative IQ score
If race times are normally distributed around 28 minutes with a standard deviation of something or other, or bowling scores were normally distributed around 180, you wouldn't conclude that if you had enough people someone could theoretically get a negative race time, or a bowling score of -10 or 310.

edit: I see now- you're right :) The formula I was thinking of is the very old one, which is like (individual score/avg. score* 100). When SD is part of the formula rather than just an assumption about the data you can totally get a negative score.
 (I helped save b3ta! the prick of misery pierced my foot on a spiiiike on, Wed 10 Dec 2014, 13:07, Reply)