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# is equal
to

2^(1) x 2^(-1/2)
=
2^(1) x 1/(2^(1/2)
=
(2^(1))/(2^(1/2))
=
2/(2^(1/2))
=
(2x2^(2.5))/(2^(1/2)x2^(2.5))
=
(2^(2.5))/(2^(3))
=
2^(2.5) x 2(-3)
=
2^(-1/2)

Therefore 2^(1/2) = 1/(2^(1/2))

enough now...

um...
(I helped save b3ta! icezebra *insert large monkey*, Tue 16 Dec 2003, 13:07, archived)