i did S2 in January and have forgotten most of itso forgive me if this is the wrong way to do it...
integral of kt^3 between 0 and 2 = 1
so (k*2^4)/4 - (k*0^4)/4 = 1
k = 1/4
As for the rest of it... i think you need to find the c.d.f. yesh?
(integral of kt^3 between 0 and 2 = 1
so (k*2^4)/4 - (k*0^4)/4 = 1
k = 1/4
As for the rest of it... i think you need to find the c.d.f. yesh?
charlie?,
Tue 20 May 2008, 20:34,
archived)
Yeah =DIf I'd not figured it out by reading around the internets some more, then you'd have been a life saver
(
Rev. Cleo still alive,
Tue 20 May 2008, 21:02,
archived)