
I thought I would ask you as you're more likely to be on than my Statistics 2 doing friends, and I'm really stuck on this. I'm having to learn S2 really quickly, as my tutor has been focusing mainly on core 3 and 4, instead of statistics, and I don't know how to find out k.
All I know is that I have to use the area beneath the curve, which is always 1.
And google is being a piece of poo and not giving me anything useful.
There's a picture beneath the questions for those who don't know enough statistics to help me.
-I figured it out! Yay!-

Uh, I'm not called Ikijigoku, that was the name of a person on a different site.
( ,
Tue 20 May 2008, 19:43,
archived)
All I know is that I have to use the area beneath the curve, which is always 1.
And google is being a piece of poo and not giving me anything useful.
There's a picture beneath the questions for those who don't know enough statistics to help me.
-I figured it out! Yay!-

Uh, I'm not called Ikijigoku, that was the name of a person on a different site.

Especially with no help.
I think I just figured it out though.
it involves integration from the f(x)
( ,
Tue 20 May 2008, 19:53,
archived)
I think I just figured it out though.
it involves integration from the f(x)

is easy to learn
i had to do a crash AS and Alevel maths course in uni
:P
( ,
Tue 20 May 2008, 20:05,
archived)
i had to do a crash AS and Alevel maths course in uni
:P

That bit is piss.
You just have to remember what do to before and after integration, and remember to do the right bits, and add the sea.
( ,
Tue 20 May 2008, 20:06,
archived)
You just have to remember what do to before and after integration, and remember to do the right bits, and add the sea.

It's revision. My exam is on friday, and I've not been taught all my work.
I got my best mark in maths last year, so my parents made me carry it on out of school.
( ,
Tue 20 May 2008, 19:50,
archived)
I got my best mark in maths last year, so my parents made me carry it on out of school.

I was just hoping some people could not help but click the link.
( ,
Tue 20 May 2008, 20:03,
archived)

and so lack that convinience. I also lack a spell checker, so I may have spelled convinience wrong. Twice.
Plus my remote is running out of batteries.
( ,
Tue 20 May 2008, 20:13,
archived)
Plus my remote is running out of batteries.

I'm very rusty in that dept I'm afraid.
I'd suggest the Derren Brown speed reading revision though.
;)
( ,
Tue 20 May 2008, 19:56,
archived)
I'd suggest the Derren Brown speed reading revision though.
;)

"I'M FUCKING READING, YEAH!"
( ,
Tue 20 May 2008, 19:57,
archived)

And I had to find it.
I think I've got it now though, it's just integration. Most of this bit is integration.
( ,
Tue 20 May 2008, 20:03,
archived)
I think I've got it now though, it's just integration. Most of this bit is integration.

so forgive me if this is the wrong way to do it...
integral of kt^3 between 0 and 2 = 1
so (k*2^4)/4 - (k*0^4)/4 = 1
k = 1/4
As for the rest of it... i think you need to find the c.d.f. yesh?
( ,
Tue 20 May 2008, 20:34,
archived)
integral of kt^3 between 0 and 2 = 1
so (k*2^4)/4 - (k*0^4)/4 = 1
k = 1/4
As for the rest of it... i think you need to find the c.d.f. yesh?