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electronics/physics chaps?
faraday's law of induction...

i've used i = I [1-e^-((Rt)/L)] and managed to get an answer of 5.58mA with a middle step of i = 0.025e^-(((300)(0.005))/1)

I know the answer is correct but how did I manage to get to that middle step? I cannot remember where the 0.025 came from and how I lost the '1-'.
The circuit has two resistors in series around the charged inductor with a value of 100ohms and 200ohms and the voltage is 5V.
I've stupidly taken the book I was using back to the libary now and bloody need it.

I'm sure this will be greeted with nothing but helpful comments....
(, Thu 9 Jul 2009, 22:11, archived)
88MPH MARTY!

(, Thu 9 Jul 2009, 22:11, archived)
Do your own homework.

(, Thu 9 Jul 2009, 22:11, archived)
I've done the homework...
I'm writing it up now and regretting cutting corners.
(, Thu 9 Jul 2009, 22:12, archived)
Torchwood

(, Thu 9 Jul 2009, 22:11, archived)
Fucking hell, I'm in a confused mood tonight and this has just messed me right up.
NEXT!
(, Thu 9 Jul 2009, 22:12, archived)
Lady Gaga

(, Thu 9 Jul 2009, 22:12, archived)
There's a lecture theatre at my uni called Faraday Lecture Theatre.
It's pretty good in there.
(, Thu 9 Jul 2009, 22:13, archived)
I can help.

(, Thu 9 Jul 2009, 22:15, archived)
just guess then.
it is what i have resorted to..
(, Thu 9 Jul 2009, 22:15, archived)
Well it looks to me as if you've used some letters and numbers for mathematical purposes, but forgotten to show your working.
Just run through the problem again and this time, show your working.

That'll be £30 please.
(, Thu 9 Jul 2009, 22:17, archived)
i could do this, once
but not these days, i need you to get me a lions penis...still attached to a lion and bring it to me, and then maybe i will be able to help you
(, Thu 9 Jul 2009, 22:15, archived)
you better get fucking remembering then
because i have the lion cock in hand now and i'm heading your way
(, Thu 9 Jul 2009, 22:17, archived)