faraday's law of induction...
i've used i = I [1-e^-((Rt)/L)] and managed to get an answer of 5.58mA with a middle step of i = 0.025e^-(((300)(0.005))/1)
I know the answer is correct but how did I manage to get to that middle step? I cannot remember where the 0.025 came from and how I lost the '1-'.
The circuit has two resistors in series around the charged inductor with a value of 100ohms and 200ohms and the voltage is 5V.
I've stupidly taken the book I was using back to the libary now and bloody need it.
I'm sure this will be greeted with nothing but helpful comments....
(, Thu 9 Jul 2009, 22:11, archived)
I'm writing it up now and regretting cutting corners.
(, Thu 9 Jul 2009, 22:12, archived)
NEXT!
(, Thu 9 Jul 2009, 22:12, archived)
It's pretty good in there.
(, Thu 9 Jul 2009, 22:13, archived)
Just run through the problem again and this time, show your working.
That'll be £30 please.
(, Thu 9 Jul 2009, 22:17, archived)