![[challenge entry]](/images/board_posticon_c.gif "Challenge Entry: Celebrity Zoo"){kind=small}
does barbie count??
From the Celebrity Zoo challenge. See all 483 entries (closed)
(
Steerable_forehead Our Lady of Blessed Acceleration,don't fail me now,
Mon 9 Jun 2003, 15:01,
archived)
can someone differentiate1-cos a=y
a-sin a=x
for me... preferably with workings :)
(a-sin a=x
for me... preferably with workings :)
lemony,
Mon 9 Jun 2003, 15:04,
archived)
Here you go:1-cos a=y is the one with the =y at the end.
a-sin a=x is the one with the =x at the end.
Oh wait, you meant a different kind of differentiate, didn't you?
(,
Mon 9 Jun 2003, 15:08,
archived)
a-sin a=x is the one with the =x at the end.
Oh wait, you meant a different kind of differentiate, didn't you?
I'm very rusty, but this might do?dy/da = sin a
dx/da =1 +cos a
dy/dx = sin a / 1+ cos a
dy/dx = x -a / 2- y
dy/dx = (x - cos^-1 (1-y)) / 2-y
I'm sure there's a better way though. Please post a kitten as payment.
(,
Mon 9 Jun 2003, 15:21,
archived)
dx/da =1 +cos a
dy/dx = sin a / 1+ cos a
dy/dx = x -a / 2- y
dy/dx = (x - cos^-1 (1-y)) / 2-y
I'm sure there's a better way though. Please post a kitten as payment.
OK done itI had to make a CORDIC engine out of lego though.
If you want the workings I have them in a placky bag
(If you want the workings I have them in a placky bag
Oscar Wildebeest,
Mon 9 Jun 2003, 15:23,
archived)
You haven't saidwith respect to what you want them differentiated.
If y = 1 + cos a
then dy/da = -sin a
but dy/dx = 0 (y is constant wrt x)
I know in your case it's fairly obvious but if you're gonna get to the stage of really understanding this stuff it's probably worth noting.
(If y = 1 + cos a
then dy/da = -sin a
but dy/dx = 0 (y is constant wrt x)
I know in your case it's fairly obvious but if you're gonna get to the stage of really understanding this stuff it's probably worth noting.
Hagbard ... it's been a long time.,
Mon 9 Jun 2003, 15:28,
archived)