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# Hahaha!
Had to look at the filename but woo!
(, Wed 31 Mar 2004, 19:15, archived)
# hey Jill
here's the bag the stone was in when we found it
(, Wed 31 Mar 2004, 19:22, archived)
# any good at maths
ton of stone travelling forwards at @80m.p.h
drops @800ft
what's the force when it lands?
I'm very curious
(, Wed 31 Mar 2004, 19:25, archived)
# I'm crap at maths, as you well know,
but I'm sure there's somewhere online where you can put in details like that and get an answer.
(, Wed 31 Mar 2004, 19:28, archived)
# thought some clever bugger on here
would answer, didn't expect you to know
after all you're a girl
runs away quickly
(, Wed 31 Mar 2004, 19:30, archived)
# V=VO + AT^2
F = MA

I could do it, but I can't be arsed either.

Edit: In lamens:

Velocity = initial velocity + acceleration x time squared.

Force = mass x acceleration
(, Wed 31 Mar 2004, 19:32, archived)
# aw go on
I've got to write a report for H.S.E.
(, Wed 31 Mar 2004, 19:34, archived)
# Oh fine, gimme a tick
(, Wed 31 Mar 2004, 19:36, archived)
# Potential
It's easier in potential energy....

mgh + 1/2mv^2
(, Wed 31 Mar 2004, 19:36, archived)
# You do it then =P
I'm on holiday and I don't care much for math at the moment.
(, Wed 31 Mar 2004, 19:46, archived)
# need to know the mass of the stone

velocity wise it'd be 32 feet per second per second.

*edit... oh a ton! oh in that case it's...


oh damn i forgot my stoneulator
(, Wed 31 Mar 2004, 19:31, archived)
# dunno about mass but
roughly 1 cubic metre of rock wieghing 1 ton, inside a big bag
(, Wed 31 Mar 2004, 19:33, archived)
# the bag would add drag to the whole shananagan


i expect it's velocity x mass / drag + curry = explosion.

or something.
(, Wed 31 Mar 2004, 19:34, archived)
# I highly doubt it
because the mass of the stone would most likely cancel out any resistance offered up by the bag.

I mean, it would.. but it would not be very noticed.
(, Wed 31 Mar 2004, 19:45, archived)
# says mass is one ton
force = mass X acelleration

convert it all to metric and voila
(, Wed 31 Mar 2004, 19:47, archived)
# Bzzt, wrong.
The force you want to know is the force exerted by the ground to change the stone's velocity back to zero when it hits. (Actually it's the reaction to that force, but Newton's Third, right?) So there is another piece of data missing: you need to know the nature of the ground the stone lands on - if it lands on mud the force will be smaller than if it landed on an expanse of concrete, because it will take longer to come to a stop, i.e. acceleration will be lower.
(, Wed 31 Mar 2004, 20:05, archived)
# Answer
692083.5 lbs force (neglecting air resistance of falling stone; I hate fluids). People should not make grad students do data entry. They go on B3ta.
(, Wed 31 Mar 2004, 19:35, archived)
# Is that a lot then?
How many pieces would dill have been smashed into?
(, Wed 31 Mar 2004, 19:37, archived)
# In mini's
It's like setting 384.4 minis on top of dill, very carefully.
(, Wed 31 Mar 2004, 19:39, archived)
# Like backwards dill/mini jenga?
Ace!
(, Wed 31 Mar 2004, 19:41, archived)
# thankee sir
considering I weigh just 64Kg and am made of soft squishy stuff, that would've smarted a bit!
(, Wed 31 Mar 2004, 19:39, archived)