b3ta.com board
You are not logged in. Login or Signup
Home » Messageboard » The Land That Scale Forgot » Message 4181480

[challenge entry] A hydrogen atom.


And if this doesn't win, there's no justice.

From the The Land That Scale Forgot challenge. See all 616 entries (closed)

(, Fri 21 Jan 2005, 16:44, archived)
# Hahahaah!
Has the world gone MAD?
(, Fri 21 Jan 2005, 16:44, archived)
# There is no justice...just me*

*DEATH
(, Fri 21 Jan 2005, 16:45, archived)
# bah
I want to see proper atomic orbitals.
(, Fri 21 Jan 2005, 16:46, archived)
# That is a proper one.
an H atom only has 1 s orbital, and you can't draw a sphere on a flat screen.
(, Fri 21 Jan 2005, 16:48, archived)
# The electron's in its ground state
and therefore in the spherical 1s orbital.

That would just look like a circle (on a computer screen)



Happy now?
(, Fri 21 Jan 2005, 16:49, archived)
# are
you sur it's blue?
(, Fri 21 Jan 2005, 16:51, archived)
# yes
/keeps fingers crossed that no one can prove him wrong
(, Fri 21 Jan 2005, 16:52, archived)
# mm...
what, an e- binding energy 13.6 eV... equivalent
to a photon with frequency of 2E16 rad/s ... is
that blue?
(, Fri 21 Jan 2005, 16:58, archived)
# well that would be the energy released
moving an electron from its ground state to infinity. Which would mean the electron was no longer in orbit around the nucleus. Which would mean we no longer had a hydrogen atom. Which would mean that that wavelength of light is not the colour of a 1s orbital.
(, Fri 21 Jan 2005, 17:00, archived)
# ok
what plausible suggests might you suggest for working out the colour of an electron orbital?
(, Fri 21 Jan 2005, 17:02, archived)
# Science team!
*fanfare and theme tune*
(, Fri 21 Jan 2005, 16:51, archived)
# *high-fives Automatic Mince*
I notice from your profile you are still at school. It may seem a bit early to be considering not doing a PhD at the minute.

But whatever you do, don't do one.
(, Fri 21 Jan 2005, 16:54, archived)
# perhaps
if you actually worked on your thesis or research??

:-)
(, Fri 21 Jan 2005, 16:59, archived)
# that wouldn't be playing fair
(, Fri 21 Jan 2005, 17:03, archived)
# No,
It has to diminish in probability density as you get further from the proton. And be infinite in size.
(, Fri 21 Jan 2005, 16:54, archived)
# I was drawing the angular component
not the density one. Feel free to draw your own, taking into account the electron density.
(, Fri 21 Jan 2005, 16:54, archived)
#
There is no angular component in an s orbital, only radial. Now geek me 'till I barf!

edit: No, I won't draw a better one. Not because I'm totally incapable*, but because I don't want to.




*is incapable
(, Fri 21 Jan 2005, 16:58, archived)
# So simple,
It made me laugh like a rancid cheeseburger.
(, Sat 22 Jan 2005, 0:15, archived)