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Playing around with seashore
![](https://groups.msn.com/_Secure/0VQAsA9Ib4ueo3wfCq9hjgPMQzboWLDIm6fXDkBD62CH2Hjgt!06gyfop2w5ouzi*XmtvoAK8D37VxPU!mw42OO2xH5oZryTr26rWQ8*MkaAW3L7SOH5B*je15LduIK2!/CombScissorsSilhouette.gif)
seashore
has no bloody gif support yet, but someday..... looked at the CVS. I passively detest C. Its a aqua/mac native GIMP project. Lets hope it gets as good as 2.2 soon! help code if you have the skilz. Tiz' your duty!
( ,
Sun 17 Apr 2005, 23:26,
archived)
![](https://groups.msn.com/_Secure/0VQAsA9Ib4ueo3wfCq9hjgPMQzboWLDIm6fXDkBD62CH2Hjgt!06gyfop2w5ouzi*XmtvoAK8D37VxPU!mw42OO2xH5oZryTr26rWQ8*MkaAW3L7SOH5B*je15LduIK2!/CombScissorsSilhouette.gif)
seashore
has no bloody gif support yet, but someday..... looked at the CVS. I passively detest C. Its a aqua/mac native GIMP project. Lets hope it gets as good as 2.2 soon! help code if you have the skilz. Tiz' your duty!
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that reminds me, have there been any captain simian and the spaaaaaaaace monkeys references on this weeks challenge yet?
( ,
Sun 17 Apr 2005, 23:30,
archived)
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I do stupid stuff when programming any language, but C does stupid stuff to ME!
( ,
Sun 17 Apr 2005, 23:32,
archived)
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And I love it. I want to have its babies. I love function pointers.
void *(*t)(void *);
t = (void *(*)(void *))return_function();
(void)t(NULL);
( ,
Sun 17 Apr 2005, 23:44,
archived)
void *(*t)(void *);
t = (void *(*)(void *))return_function();
(void)t(NULL);
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I also love the weakly typedness of C.
( ,
Sun 17 Apr 2005, 23:51,
archived)
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but I don't know what that says.
It looks like it declares a function that takes a void pointer, and then the function is cast as a pointer (and it returns a void pointer). What does that mean?
*gets out K&R*
*remembers brackets associate left to right*
hang on a minute.
OK, I vaguely remember that the parentheses are needed in order to declare a pointer to a function instead of just declaring a function that returns a handle. I get the impression that what you've made is a pointer to a function that takes a pointer to a function and returns a pointer to a function, maybe, not sure.
*goes to bed*
( ,
Mon 18 Apr 2005, 0:03,
archived)
It looks like it declares a function that takes a void pointer, and then the function is cast as a pointer (and it returns a void pointer). What does that mean?
*gets out K&R*
*remembers brackets associate left to right*
hang on a minute.
OK, I vaguely remember that the parentheses are needed in order to declare a pointer to a function instead of just declaring a function that returns a handle. I get the impression that what you've made is a pointer to a function that takes a pointer to a function and returns a pointer to a function, maybe, not sure.
*goes to bed*