I wonder
what the minimum number of tickets is to win at least one prize (i.e. get 3 of the numbers). I could probably work it out but don't care enough :)
(Richy_T hundreds if not thousands of dollars, Tue 12 May 2009, 17:08, 1 reply)

This is a pretty hard problem
I've been thinking about it for ten minutes now and still can't work it out. My feeling is that it's a very, very high number. I'll think about it some more.
( flatfrog Staring vacantly into space, Tue 12 May 2009, 21:16, closed)

I think I got it
You'd have to guarantee 3 numbers out of 6 leaving 3 that don't matter so I reckon every combination of 3 from 46 numbers.

46 * 45 * 44 = £91,080.
( stopmeandslapme Cometh the hour, cometh your mum, Wed 13 May 2009, 8:10, closed)