they're not exactlyridiculous numbers, mind you I don't know that many numbers that are.
(
butchbint,
Tue 16 Dec 2003, 12:56,
archived)
Not ridiculousvery useful for working out RMS values...
( Dr. trouser,
Tue 16 Dec 2003, 13:03,
archived)
is equalto
2^(1) x 2^(-1/2)
=
2^(1) x 1/(2^(1/2)
=
(2^(1))/(2^(1/2))
=
2/(2^(1/2))
=
(2x2^(2.5))/(2^(1/2)x2^(2.5))
=
(2^(2.5))/(2^(3))
=
2^(2.5) x 2(-3)
=
2^(-1/2)
Therefore 2^(1/2) = 1/(2^(1/2))
enough now...
um...
(2^(1) x 2^(-1/2)
=
2^(1) x 1/(2^(1/2)
=
(2^(1))/(2^(1/2))
=
2/(2^(1/2))
=
(2x2^(2.5))/(2^(1/2)x2^(2.5))
=
(2^(2.5))/(2^(3))
=
2^(2.5) x 2(-3)
=
2^(-1/2)
Therefore 2^(1/2) = 1/(2^(1/2))
enough now...
um...
icezebra *insert large monkey*,
Tue 16 Dec 2003, 13:07,
archived)