
Consider a cavity in a fluid, with a time dependent pressure p(t), the radius R(t) of the bubble is:

( ,
Sun 18 May 2008, 12:32,
archived)


that first part of the equation should just be
R-(p&-1) as dividing by P would cancel the others out....however, how can you have infinity in the equation?
( ,
Sun 18 May 2008, 12:36,
archived)
R-(p&-1) as dividing by P would cancel the others out....however, how can you have infinity in the equation?

rho is density, p(R) the pressure at radius R, p(infinity) the asymptotic limit of the pressure as R is tended to infinity
( ,
Sun 18 May 2008, 12:38,
archived)

*wistles*
( ,
Sun 18 May 2008, 12:48,
archived)

and the infinity is a subscript on a p, which is like the pressure at an infinite distance from the bubble (cavity)
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Sun 18 May 2008, 12:39,
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that looks enormously like the equivalent of the Friedmann equation in a McVittie spacetime. I don't know what I could do with that but it might be worth looking back over an aborted project in the McVittie spacetime.... Hmmmm.
Edit: I probably mean the Raychaudhuri equation rather than the Friedmann equation, since that's the same as the FLRW case.
( ,
Sun 18 May 2008, 12:37,
archived)
Edit: I probably mean the Raychaudhuri equation rather than the Friedmann equation, since that's the same as the FLRW case.

one tiny little pocket of it. i'm shit at the rest of it.
( ,
Sun 18 May 2008, 12:46,
archived)

*runs back to fluid dynamics*
( ,
Sun 18 May 2008, 12:49,
archived)