b3ta.com board
You are not logged in. Login or Signup
Home » Messageboard » Message 9039414 (Thread)

# Personally
I'd do it as (1/1)+1*(1+1+1)
(, Fri 19 Dec 2008, 16:50, archived)
# But that works out as 4
Because multiplication is done before adding. You need more brackets: ((1/1)+1)*(1+1+1).
(, Fri 19 Dec 2008, 17:01, archived)
# (1+1+1)*(1+1+1) = 9
I win.

If they allow powers, you can get 27 with

(1+1+1)^(1+1+1) = 3^3 = 3*3*3 = 9*3 = 27
(, Fri 19 Dec 2008, 20:56, archived)
# I'm afraid they don't
(, Sat 20 Dec 2008, 2:00, archived)
# That's nothing
I could make 111,111!

(, Mon 22 Dec 2008, 12:24, archived)