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This is a question Off Topic

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(, Sun 1 Apr 2001, 1:00)
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But
2^(x+y)^2/2^(x-y)^2 = (2^(-2)^2)/2^(-1 - (-1) )^2 = 16/1 = 16.
(, Thu 20 Dec 2012, 15:49, 1 reply, 13 years ago)
That's if x and y = 1 not if xy=1

(, Thu 20 Dec 2012, 15:51, Reply)
Ah. Yes.
You win.
(, Thu 20 Dec 2012, 15:52, Reply)

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