I'm really shocked by K3b/-\b's stats quote
what are the chances of that being randomly selected?
(
Prof UnderCover evitable,
Wed 7 Jan 2009, 9:51,
archived)
simple, assuming equal probabilities:
let n be my number of posts (110) in the past week
and m be the number of those which are 'would' (there's 2 of them) so:
p=m/n = 2/110 = 1/55
(
k3b/-\b Peace man.,
Wed 7 Jan 2009, 9:56,
archived)