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( , Sun 1 Apr 2001, 1:00)
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It's been done before, but I quite like it so here goes...
Imagine an airplane on a treadmill. However fast the wheels of the plane go, the treadmill matches the speed, but backwards.
Will the plane take off?
Discuss.
( , Tue 9 Jun 2009, 1:22, 8 replies, latest was 16 years ago)

It's all about the airspeed over the wings: the wings need to be moving fast enough for the airspeed to provide enough downward force to create lift (the thing about low pressure above the wing sucking the plane skywards is apparently not as important as we were all told in school).
Or something. I don't know, I'm not a physicist.
Now, if the question was "could a very strong wind blowing toward a stationary plane cause it to take off?" that'd be a different matter...
( , Tue 9 Jun 2009, 1:56, Reply)

The answer is yes and no, and depends on the definition of the question:
answers.google.com/answers/threadview/id/731766.html
( , Tue 9 Jun 2009, 2:40, Reply)

No. The plane taking off depends on the speed of the air over the wings, not to do with how fast the wheels are turning.
( , Tue 9 Jun 2009, 7:45, Reply)

Unlike most ground based transport, aeroplanes don't get their motive force from mechanically turning the wheels. The force comes from an engine which moves air, whether by propellor or turbine, and the reactionary force moves the aircraft forwards. If the wheels were driven instead, then as soon as the plane took off, the force would cease and it would quickly drop back down again.
( , Tue 9 Jun 2009, 8:23, Reply)

blag.xkcd.com/2008/09/09/the-goddamn-airplane-on-the-goddamn-treadmill/
( , Tue 9 Jun 2009, 9:11, Reply)

Once the friction overcomes the reversiness of the treadmill. It would be a bit sloppy, but it would take off.
( , Tue 9 Jun 2009, 11:59, Reply)
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