Almost as hard to believe as the factthat it seems to matter so much that people are bothering to count
(
butchbint,
Tue 16 Dec 2003, 12:51,
archived)
Nobecause I haven't seen it and nor do I give a flying fuck, as inferred by my previous post
( butchbint,
Tue 16 Dec 2003, 12:53,
archived)
damn!Thats something i would have liked to have seen:)
( monkeymanblue mathematically safe,
Tue 16 Dec 2003, 12:56,
archived)
I'm surprisedthat people are going on about the number of Saddam Clause posts, that doesn't mean I want to know how many there have been.
( butchbint,
Tue 16 Dec 2003, 12:58,
archived)
there you go then30 + images on the same joke.... tedious after the first 5
(,
Tue 16 Dec 2003, 13:04,
archived)
30 pictures of the same jokeis hardly a new phenomenon round here, is it!
( monkeymanblue mathematically safe,
Tue 16 Dec 2003, 13:08,
archived)
You could alwaysdo something else if it bothers you that much.
/grouch
edit: sorry, inadvertently hit capslock then
(/grouch
edit: sorry, inadvertently hit capslock then
butchbint,
Tue 16 Dec 2003, 13:08,
archived)
they're not exactlyridiculous numbers, mind you I don't know that many numbers that are.
( butchbint,
Tue 16 Dec 2003, 12:56,
archived)
Not ridiculousvery useful for working out RMS values...
( Dr. trouser,
Tue 16 Dec 2003, 13:03,
archived)
is equalto
2^(1) x 2^(-1/2)
=
2^(1) x 1/(2^(1/2)
=
(2^(1))/(2^(1/2))
=
2/(2^(1/2))
=
(2x2^(2.5))/(2^(1/2)x2^(2.5))
=
(2^(2.5))/(2^(3))
=
2^(2.5) x 2(-3)
=
2^(-1/2)
Therefore 2^(1/2) = 1/(2^(1/2))
enough now...
um...
(2^(1) x 2^(-1/2)
=
2^(1) x 1/(2^(1/2)
=
(2^(1))/(2^(1/2))
=
2/(2^(1/2))
=
(2x2^(2.5))/(2^(1/2)x2^(2.5))
=
(2^(2.5))/(2^(3))
=
2^(2.5) x 2(-3)
=
2^(-1/2)
Therefore 2^(1/2) = 1/(2^(1/2))
enough now...
um...
icezebra *insert large monkey*,
Tue 16 Dec 2003, 13:07,
archived)