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rob, Sun 1 Apr 2001, 1:00)
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if xy=1 what is the value of: 2(x+y)^2/2 (x-y)^2 ?(
Fucking hell Jeff I am not a robot, Thu 20 Dec 2012, 15:36,
1 reply,
13 years ago)
If you expand it you get.2x^2+2xy+2y^2
2x^2-2xy-2y^2
which I think cancels down to either 1 or -1
(, Thu 20 Dec 2012, 15:48, Reply)
But2^(x+y)^2/2^(x-y)^2 = (2^(-2)^2)/2^(-1 - (-1) )^2 = 16/1 = 16.
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Fucking hell Jeff I am not a robot, Thu 20 Dec 2012, 15:49,
Reply)
Only if it's actually 2^(x+y)^2/2^(x-y)^2(
The Light in Chains don't touch the Pope's boner, Thu 20 Dec 2012, 15:58,
Reply)
As explained in my* post at www.manhattangmat.com/forums/if-xy-1-what-is-the-value-of-2-x-y-2-2-x-y-2-t2912.html
*you can't prove it isn't
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The Light in Chains don't touch the Pope's boner, Thu 20 Dec 2012, 16:00,
Reply)
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