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(, Sun 1 Apr 2001, 1:00)
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Well
Using the standard equations of motion, s=0.5at2. So a=2s/t2. Therefore if s=110m and t=12s, a=1.52ms-2.

And if v=at, then v=18.3ms-1

which is about 40mph.

Although intuitively you'd expect the acceleration and hence the velocity to be a bit more than that.
(, Tue 30 Jun 2009, 10:46, 5 replies, latest was 17 years ago)
Thanks K2!
I don't doubt your maths, but I do doubt my own intuition now!
(, Tue 30 Jun 2009, 10:48, Reply)
This makes more sense now I see it
Going to have to double check my maths now and get back to you. Always willing to be proved wrong.
(, Tue 30 Jun 2009, 10:50, Reply)
damn you
took me longer to decide whether to type it up or not!
(, Tue 30 Jun 2009, 10:51, Reply)
It's actually 40.938mph
using 5280'/mile and 1m=3.281 feet.
(, Tue 30 Jun 2009, 11:08, Reply)
Given the errors in the length of the tower
and the time, 40mph is close enough!
(, Tue 30 Jun 2009, 11:10, Reply)
Yeah
Surely we can get more precise data though.

And I just converted your answer into mph.
(, Tue 30 Jun 2009, 11:16, Reply)
Nope
Sure Nasa sent men to the moon but the only guys that could operate a tape measure were drunk...always.
(, Tue 30 Jun 2009, 11:17, Reply)
Well if half the stuff about NASA is true
This fact doesn't phase me in the slightest!
(, Tue 30 Jun 2009, 11:49, Reply)
Thing is,
rockets don't have constant acceleration do they?

They provide constant thrust (ish) but their mass changes.
(, Tue 30 Jun 2009, 11:42, Reply)
but over a short period
you can assume a constant average acceleration without too much trouble
(, Tue 30 Jun 2009, 11:49, Reply)
Well
if you're going to be making assumptions... ;)
(, Tue 30 Jun 2009, 11:54, Reply)
I'm an engineer
that's what we do
(, Tue 30 Jun 2009, 11:59, Reply)

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